a) (p ↔ q) ⊕ (¬p ↔¬r) b) (p → q) ∧ (¬p → r)

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Solution.

This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.

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Question ID: mtid-5-stid-8-sqid-2831-qpid-1388