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Archangel Macsika

An urn contains numbered balls. How many ways can we choose balls out of the urn (without repetition, the order does not count)6 63

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Let's say we have 63 balls in the urn, and need to choose 6 balls. Six balls have 6! orders, thus the number of choices for choosing 6 balls out of 63 without any repetition such that the order does not count is \dfrac{63!}{57!\times6!} = 407673126.

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Question ID: mtid-5-stid-8-sqid-3170-qpid-1869