Calculate (by hand) the appropriate truth table to prove or disprove the following: (p → q) ∧ (¬p → r) ⇒ (q ∨ r) If it is invalid, give a counterexample; otherwise, explain why it is valid.
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As, is a Tautology (always true) ;
Thus; the implication holds.
It is valid as the condtional is a Tautolgy; hece the Implication holds.