j=0 ∑ 8 ( j 8 ) (j+1)(j+2) 1 =1⋅ (0+1)(0+2) 1 +8\cdot\dfrac{1}{(1+1)(1+2)}+28\cdot\dfrac{1}{(2+1)(2+2)}+8⋅ (1+1)(1+2) 1 +28⋅ (2+1)(2+2) 1 +56\cdot\dfrac{1}{(3+1)(3+2)}+70\cdot\dfrac{1}{(4+1)(4+2)}+56⋅ (3+1)(3+2) 1 +70⋅ (4+1)(4+2) 1 +56\cdot\dfrac{1}{(5+1)(5+2)}+28\cdot\dfrac{1}{(6+1)(6+2)}+56⋅ (5+1)(5+2) 1 +28⋅ (6+1)(6+2) 1 +8\cdot\dfrac{1}{(7+1)(7+2)}+1\cdot\dfrac{1}{(8+1)(8+2)}+8⋅ (7+1)(7+2) 1 +1⋅ (8+1)(8+2) 1 =\dfrac{1013}{90}= 90 1013
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