Archangel Macsika
Construct a truth table for each of these compound propositions: i) (p ⇔ q) ⇔ (r ⇔ s) ii) (p ⨁ q) ∨ (p ⨁ ¬q)
The Answer to the Question
is below this banner.
Can't find a solution anywhere?
NEED A FAST ANSWER TO ANY QUESTION OR ASSIGNMENT?
Get the Answers Now!You will get a detailed answer to your question or assignment in the shortest time possible.
Here's the Solution to this Question
i. Truth Table for: (p ⇔ q) ⇔ (r ⇔ s)
| p | q | r | s | p ⇔ q | r ⇔ s | (p ⇔ q) ⇔ (r ⇔ s) |
|---|---|---|---|---|---|---|
| T | T | T | T | T | T | T |
| T | T | T | F | T | F | F |
| T | T | F | T | T | F | F |
| T | T | F | F | T | T | T |
| T | F | T | T | F | T | F |
| T | F | T | F | F | F | T |
| T | F | F | T | F | F | T |
| T | F | F | F | F | T | F |
| F | T | T | T | F | T | F |
| F | T | T | F | F | F | T |
| F | T | F | T | F | F | T |
| F | T | F | F | F | T | F |
| F | F | T | T | T | T | T |
| F | F | T | F | T | F | F |
| F | F | F | T | T | F | F |
| F | F | F | F | T | T | T |
ii. Truth Table for: (p ⨁ q) ∨ (p ⨁ ¬q)
| p | q | ¬q | p ⨁ q | p ⨁ ¬q | (p ⨁ q) ∨ (p ⨁ ¬q) |
|---|---|---|---|---|---|
| T | T | F | F | T | T |
| T | F | T | T | F | T |
| F | T | F | T | F | T |
| F | F | T | F | T | T |