Let us construct the trush table for the following compound propositions:
a) p⊕p
p01p⊕p00
b) p⊕¬p
p01¬p10p⊕¬p11
c) p⊕¬q
p0011q0101¬q1010p⊕¬q1001
d) ¬p⊕¬q
p0011q0101¬p1100¬q1010¬p⊕¬q0110
e) (p⊕q)∨(p⊕¬q)
p0011q0101¬q1010p⊕¬q1001p⊕q0110(p⊕q)∨(p⊕¬q)1111
f ) (p⊕q)∧(p⊕¬q)
p0011q0101¬q1010p⊕¬q1001p⊕q0110(p⊕q)∧(p⊕¬q)0000