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Determine how many bit strings of length 5 can be formed ,where three consecutive 0s are not allowed

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The number of elements of the set of different binary strings of length 5 is 2^5=32.

Determine the number of bit strings of length 5 that contain three consecutive 0s.


\begin{matrix} 0 & 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0 & 1\\ 0 & 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1 & 1\\ \\ 1 & 0 & 0 & 0 & 0\\ 1 & 0 & 0 & 0 & 1\\ \\ 0 & 1 & 0 & 0 & 0\\ 1 & 1 & 0 & 0 & 0\\ \end{matrix}

How many bit strings of length 5 can be formed ,where three consecutive 0s are not allowed


32-8=24

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Question ID: mtid-5-stid-8-sqid-2700-qpid-1170