Encrypt the message ATTACK using the RSA cryptosystem with n = 43 · 59 and e = 13, translating each letter into integers and grouping together pairs of integers, as done in example 11 in the textbook and in the classnotes
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RSA uses a public key, found from the product of 2 large primes. In yhe given case it is they selected 43 and 59, so the public key is 43*59 = 2537. You were also given e = 13. The English alphabet contains 26 letters, and there is two ways to mark the letters: from 0 to 25 or from 1 to 26. Lets mark them from 1 to 26(A - 1, B - 2 etc). The logic of encrypt next: We transform each letter into the numeric form using alphabet above(A - 1, T - 20, C - 3, K - 16) and encrypt it using the next formula: , where m - encrypted letter, m - numerical form of the letter, e - public exponent, q - public key
In the given case:
So, the encrypted message is 114351435110871225