Express the negations of each of these statements so that all negation symbols immediately precede predicates. ∃x∃y(Q(x, y) ↔ Q(y, x))

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$By \space steps: \space \\ 1)\forall \space x\forall \space y\neg(Q(x,y)\leftrightarrow \space Q(y,x))\\ 2)\forall \space x\forall \space y(Q(x,y) \space \oplus \space Q(y,x)) \\ where \space \oplus \space is \space exclusive \space and \space exhaustive\\ hence \space answer \space is \space ∀x∀y(Q(x,y)⊕Q(y,x))$ $B y s t e p s : 1) \forall x \forall y \neg (Q (x, y) \leftrightarrow Q (y, x)) 2) \forall x \forall y (Q (x, y) \oplus Q (y, x)) w h ere \oplus i s e x c l u s i v e an d e x ha u s t i v e h e n ce an s w er i s \forall x \forall y (Q (x, y) \oplus Q (y, x))$

Express the negations of each of these statements so that all negation symbols immediately precede predicates. ∃x∃y(Q(x, y) ↔ Q(y, x))

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Question ID: mtid-5-stid-8-sqid-2741-qpid-1211