Solution to i. false: 4+3>64+3>6 ii. true: 1+3<61+3<6 iii. false: 2\cdot1^2+1=32⋅1 2 +1=3 2\cdot2^2+2=102⋅2 2 +2=10 2\cdot3^2+3=212⋅3 … - Sikademy
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Archangel Macsika

i. false: 4+3>64+3>6 ii. true: 1+3<61+3<6 iii. false: 2\cdot1^2+1=32⋅1 2 +1=3 2\cdot2^2+2=102⋅2 2 +2=10 2\cdot3^2+3=212⋅3 2 +3=21 2\cdot4^2+4=362⋅4 2 +4=36

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i.

false: 4+3>6


ii.

true: 1+3<6


iii.

false:

2\cdot1^2+1=3

2\cdot2^2+2=10

2\cdot3^2+3=21

2\cdot4^2+4=36

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