[T] Find \mathbb{Q}\cup \mathbb{N}Q∪N ?

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$\N = \{0, 1, 2, 3, …\},$ the set of all natural numbers.

$Q= \{p∕q ∣ p ∈ \Z, q ∈ \Z, and \ q\not=0\}$ and q ≠ 0}, the set of all rational numbers.

Then

$Q∪\N=Q$

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