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## Here's the Solution to this Question

(a)

If $y_1=y_2,$ then $x_1=x_2=>$ One-to-one.

For every $y\in \R$ exists $x\in \R$ such that $x=y=>$ Onto

$f(x)=x$ is One-to-one correspondence (a bijection).

(b)

$|-2|=2=|2|$

If $y=-2,$ then there is no $x\in \R$ such that $|x|=-2.$

$f(x)=|x|$ is neither One-to-one nor Onto.

(c)

If $y_1=y_2,$ then $x_1+1=x_2+1=>x_1=x_2=>$ One-to-one.

For every $y\in \R$ exists $x\in \R$ such that $x=y-1=>$ Onto

$f(x)=x+1$ is One-to-one correspondence (a bijection).

(d)

$(-2)^2=4=(2)^2$

If $y=-4,$ then there is no $x\in \R$ such that $x^2=-4.$

$f(x)=x^2$ is neither One-to-one nor Onto.

(e)

If $y_1=y_2,$ then $x_1^3=x_2^3=>(x_1-x_2)(x_1^2+x_1x_2+x_2^2)=0$

$=>x_1=x_2=>$ One-to-one.

For every $y\in \R$ exists $x\in \R$ such that $x=\sqrt[3]{y}=>$ Onto

$f(x)=x^3$ is One-to-one correspondence (a bijection).

(f)

$0-(0)^2=0=1-(1)^2$

If $y=1,$ then there is no $x\in \R$ such that $x-x^2=1.$

$f(x)=x-x^2$ is neither One-to-one nor Onto.

(g)

$Floor(0.2)=0=Floor(0.5)$

If $y=0.5,$ then there is no $x\in \R$ such that $Floor(x)=0.5.$

$f(x)=Floor(x)$ is neither One-to-one nor Onto.

(h)

$Ceiling(0.2)=1=Ceiling(0.5)$

If $y=0.5,$ then there is no $x\in \R$ such that $Ceiling(x)=0.5.$

$f(x)=Ceiling(x)$ is neither One-to-one nor Onto.

(i)

If $y_1=y_2,$ then $-3x_1+4=-3x_2+4=>-3x_1=-3x_2$

$=>x_1=x_2=>$ One-to-one.

For every $y\in \R$ exists $x\in \R$ such that $x=\dfrac{-y+4}{3}=>$ Onto

$f(x)=-3x+4$ is One-to-one correspondence (a bijection).

(j)

$-3(-1)^2+7=4=-3(1)^2+7$

If $y=8,$ then there is no $x\in \R$ such that $x^2=8.$

$f(x)=-3x^2+7$ is neither One-to-one nor Onto.