1. Find a relation R such that 𝑥+𝑦 2 >1 if A = {0,1, 2} and B ={0, 1, 2, 3}.

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Let us find a relation $R\subset A\times B$ such that $(x,y)\in R$ iff $𝑥+𝑦^2 >1$ if $A =\{0,1, 2\}$ and $B =\{0, 1, 2, 3\}.$

It follows that

$R=\{(0,2),(0,3),(1,1),(1,2),(1,3),$

$(2,0),(2,1),(2,2),(2,3)\}.$

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Question ID: mtid-5-stid-8-sqid-629-qpid-514