given that the function f(x) = 4x + 1 , find a formula for f-1(x)

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$f(x)=y=4x+1 \\\Rightarrow y-1=4x \\\Rightarrow \dfrac{y-1}4=x \\\therefore f^{-1}(x)=\dfrac{x-1}4$

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Question ID: mtid-5-stid-8-sqid-2941-qpid-1640