Solution to Given three sets A, B, and C. Suppose we know that the union of the … - Sikademy
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Archangel Macsika

Given three sets A, B, and C. Suppose we know that the union of the three sets has cardinality 182. Further, |A| = 92, |B| = 41, |C| = 118. Also, |A ∩ B| = 15, |A ∩ C| = 42, and |A ∩ B ∩ C| = 10. Find |B ∩ C|.

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Solution:

Given, |A U B U C| = 182, |A| = 92, |B| = 41, |C| = 118. Also, |A ∩ B| = 15, |A ∩ C| = 42, and |A ∩ B ∩ C| = 10

We know that,

|A U B U C| = |A| + |B| + |C| - |A∩B| -|A∩C| - |B∩C| + |A∩B∩C|

Putting given values.

182 = 92 + 41 + 118 -15 -42 -|B∩C| +10

\Rightarrow182 = 204 -|B∩C|

\Rightarrow|B∩C| = 204 - 182

\Rightarrow|B∩C| = 22

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