Given three sets A, B, and C. Suppose we know that the union of the three sets has cardinality 182. Further, |A| = 92, |B| = 41, |C| = 118. Also, |A ∩ B| = 15, |A ∩ C| = 42, and |A ∩ B ∩ C| = 10. Find |B ∩ C|.
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Solution:
Given, |A U B U C| = 182, |A| = 92, |B| = 41, |C| = 118. Also, |A ∩ B| = 15, |A ∩ C| = 42, and |A ∩ B ∩ C| = 10
We know that,
|A U B U C| = |A| + |B| + |C| - |A∩B| -|A∩C| - |B∩C| + |A∩B∩C|
Putting given values.
182 = 92 + 41 + 118 -15 -42 -|B∩C| +10
182 = 204 -|B∩C|
|B∩C| = 204 - 182
|B∩C| = 22