How many bit strings can be formed by using seven 1s and nine 0s?
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There are Seven 1's and nine 0's so in all there are total 7 + 9 = 16 positions for the placement of 1's and 0's
Total number of the formation of bit strings is given by = positioning seven 1's in 16 positions and filling up the remaining 9 positions with 0's = 16C7 * 9C9 = 11440*1 = 11440
Hence, 11440 different bit strings can be formed by using seven 1s and nine 0s