how many 2-digit or 3-digits numbers can be formed using the digits 1,2,3,4,5,6,8 and 9 if no repetition is allowed ?

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By Combinatorial Product Rule, the number of 2-digit numbers is equal to $8\cdot 7= 56,$ the number of 3-dogit numbers is equal to $8\cdot 7\cdot 6=336.$

Then the Combinatorial Sum Rule implies that the number of 2-digit or 3-digit numbers is equal to $56+336=392.$

how many 2-digit or 3-digits numbers can be formed using the digits 1,2,3,4,5,6,8 and 9 if no repetition is allowed ?

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Question ID: mtid-5-stid-8-sqid-265-qpid-152