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How many number of strings that can be formed by ordering the letters given: (a) SCHOOL (b) CLASSICS

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Let us use the formula for permutations with repetitions.


(a) The number of strings that can be formed by ordering the letters of the string SCHOOL is equal to


P_6(2,1,1,1)=\frac{6!}{2!1!1!1!}=\frac{720}2=360.

(b) The number of strings that can be formed by ordering the letters of the string CLASSICS is equal to


P_8(3,2,1,1,1)=\frac{8!}{3!2!1!1!1!}=\frac{40320}{12}=3360.

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