**How many number of strings that can be formed by ordering the letters given: (a) SCHOOL (b) CLASSICS**

The **Answer to the Question**

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**Here's the Solution to this Question**

Let us use the formula for permutations with repetitions.

(a) The number of strings that can be formed by ordering the letters of the string SCHOOL is equal to

$P_6(2,1,1,1)=\frac{6!}{2!1!1!1!}=\frac{720}2=360.$

(b) The number of strings that can be formed by ordering the letters of the string CLASSICS is equal to

$P_8(3,2,1,1,1)=\frac{8!}{3!2!1!1!1!}=\frac{40320}{12}=3360.$