Solution to how to solve power set? {12,34,{45}, 56} - Sikademy
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how to solve power set? {12,34,{45}, 56}

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Let A = {12,34,{45}, 56}

The subset of A are

{},{12},{34},{{45}},{56},{12,34},{12,{45}},{12,56},{34,{45}},{34,56},{{45},56},{12,34,{45}},{12,34,56},{12,{45},56},{34,{45},56},{12,34,{45},56}

Thus, Power set of A is

P(A) = {{},{12},{34},{{45}},{56},{12,34},{12,{45}},{12,56},{34,{45}},{34,56},{{45},56},{12,34,{45}},{12,34,56},{12,{45},56},{34,{45},56},{12,34,{45},56}}

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Question ID: mtid-5-stid-8-sqid-732-qpid-617