**If π = {1,2,3,4,5,6,7,8,9,10,11,12}, π΄ = {2,3,5,6}, π΅ = { 1,5,7,8,10,12}, πΆ = {8,10,11,12}. πΉπππ π΄ βͺ π΅, π΄ β π΅, π΅ β πΆ, |π(π΄)|**

The **Answer to the Question**

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**Here's the Solution to this Question**

a.

The union of the sets A and B, denoted byΒ $A\cup B,$Β is the set that contains those elements that are either in A or in B, or in both.

$A\cup B=\{1,2,3,5,6,7,8,10,12\}$

b.

The symmetric difference of A and B, denoted by A β B, is the set containing those elements in either A or B, but not in both A and B.

$π΄ β π΅=\{1,2,3,6,7,8,10,12\}$

c.

The difference of B and C, denoted byΒ $π΅ β πΆ$Β , is the set containing those elements that are in B but not in C.Β

$π΅ β πΆ=\{1,5,7\}$

d.

Cardinality denotesΒ the total number of elements in the power set. It is denoted by |P(A)|. The cardinality of a power set for a set ofΒ $n$Β elements is given byΒ $2^n$

$|π(π΄)|=2^4=16$