Solution to In how many ways can a committee of 5 teachers and 4 students be chosen … - Sikademy
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In how many ways can a committee of 5 teachers and 4 students be chosen from 9 teachers and 15 students ?

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The 4 students can be chosen out of 15 in ^{15}C_4=\binom{15}{4}={15\times 14\times13\times12\over4\times3\times2}=1365 ways.

The 5 teachers can be chosen out of 9 in ^{9}C_5=\binom{9}{5}={9\times 8\times7\times7\times6\over4\times3\times2}=126 ways.

Hence, the committee can be formed in 1365\times126=171990 ways.


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