In how many ways the word scooter be arranged when repetition is not allowed.

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The number of different permutations of $n$ objects, where there are $n_1$ indistinguishable objects of type 1, $n_2$ indistinguishable objects of type 2, … , and $n_k$ indistinguishable objects of type k, is

$\dfrac{n!}{n_1!n_2!...n_k!}$

SCOOTER - 7 letters

$\dfrac{7!}{2!}=2520$

The word scooter can be arranged in2520 ways when repetition is not allowed.

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Question ID: mtid-5-stid-8-sqid-3088-qpid-1787