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## Here's the Solution to this Question

Using Venn diagram, we have:

Let $a$ be the number of students that study all the 3 subjects, $b$ be the number of students that study biology and technical drawing but not chemistry, $c$ be the number of students that study biology only.

We know that 35 students study chemistry. It is $10+10+12+a=35$ . So, $a=35-10-10-12=3$ .

Also it is known that 30 students study technical drawing. That is $10+11+a+b=30$ . So, $b=30-10-11-a=30-10-11-3=6$ .

There are 60 students. Therefore, $10+10+11+12+a+b+c=60$ .

We have $c=60-10-10-11-12-a-b=60-10-10-11-12-3-6=8$ .

We can find the number of students that study biology. That is $12+a+b+c=12+3+6+8=29$ .

Answer: 3 students study all the 3 subjects; 6 students study biology and technical drawing but not chemistry; 8 students study biology only; 29 students study biology.

Using Venn diagram, we have:

Let $a$ be the number of students that study all the 3 subjects, $b$ be the number of students that study biology and technical drawing but not chemistry, $c$ be the number of students that study biology only.

We know that 35 students study chemistry. It is $10+10+12+a=35$ . So, $a=35-10-10-12=3$ .

Also it is known that 30 students study technical drawing. That is $10+11+a+b=30$ . So, $b=30-10-11-a=30-10-11-3=6$ .

There are 60 students. Therefore, $10+10+11+12+a+b+c=60$ .

We have $c=60-10-10-11-12-a-b=60-10-10-11-12-3-6=8$ .

We can find the number of students that study biology. That is $12+a+b+c=12+3+6+8=29$ .

Answer: 3 students study all the 3 subjects; 6 students study biology and technical drawing but not chemistry; 8 students study biology only; 29 students study biology.