The Answer to the Question
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Here's the Solution to this Question
Suppose m and n are odd. then:
is odd number.
So, m is even or n is even.
(the set of rational numbers)
(the set of irrational numbers)
Let us assume that , ie is rational, then:
st (since x is rational ), and (since the sum is rational).
Therefore, we can write;
And so y can be written as a fraction y is rational.
But we initially asserted that y was irrational and hence we have a contradiction, and so the sum
x+y cannot be rational and hence it must be irrational.
S(x): "in your class"
P(x): "is perfect"
"Someone in your class is perfect"
by DeMorgan’s Laws:
"Everybody are in class, or everybody are perfect ".
I don’t feel good I do not go walking
I do not go walking it’s cold or it’s windy