Solution to Let A= {0, 1, 2, 3} and define relations R, S and T on A … - Sikademy
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Archangel Macsika

Let A= {0, 1, 2, 3} and define relations R, S and T on A as follows: R= { (0,0),(0,1),(0,3),(1,0),(1,1),(2,2),(3,0),(3,3)} S= {(0, 0),(2,2),(1,1), (0, 2), (0, 3), (2, 3),(2,2)} T= {(0, 1), (2, 3),(0,0),(2,2),(1,0),(3,3),(3,2)} i. Is R Reflexive? Symmetric? AntiSymmetric? ii. Is S Reflexive? Symmetric? AntiSymmetric? iii. Is T Reflexive? Symmetric? AntiSymmetric

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Solution:

Given, A= {0, 1, 2, 3}

R= { (0,0),(0,1),(0,3),(1,0),(1,1),(2,2),(3,0),(3,3)}

S= {(0, 0),(2,2),(1,1), (0, 2), (0, 3), (2, 3),(2,2)}

T= {(0, 1), (2, 3),(0,0),(2,2),(1,0),(3,3),(3,2)}

Reflexive: (a,a)\in R\forall a\in A

Symmetric: (a,b)\in R\Rightarrow (b,a)\in R, \forall a,b\in A

Anti-Symmetric: (a,b)\in R,(b,a)\in R,\Rightarrow a=b, \forall a,b\in A

(i) Using these definitions, R is reflexive, symmetric but not anti-symmetric as (0,3),(3,0)\in R but 0\ne3

(ii) S is not reflexive as (3,3) is not in S.

S is symmetric and anti-symmetric.

(iii) T is not reflexive as (1,1) is not in T.

T is symmetric.

But T is not anti-symmetric as (0,1),(1,0) \in T but 1\ne 0

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