Let R be the relation from A={2,3,4,5} to B={3,6,7,10} defined by ‘x divides y’, (a) thenR^(-1) is equal to: (b) Is R an equivalence relation?

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We have $R=\{(2,6),(2,10),(3,3),(3,6),(5,10)\}$ , then $R^{-1}=\{(6,2),(10,2),(3,3),(6,3),(10,5)\}$ .

$R$ is not an equivalnce relation, because $A$ - domain of $R$ not equals $B$ - range of $R$ .

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