Let f: A\to→ B and g: B\to→ C be functions. Show that if g o f is onto, then g is onto.
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Suppose that g ◦ f is onto.
Let z ∈ C.
Then since g ◦ f is onto, there exists x ∈ A such that
(g ◦ f)(x) = g(f(x)) = z
Therefore if we let y = f(x) ∈ B,
then g(y) = z.
Thus g is onto