Solution to List the members of the following sets 1. {x| x is real numbers and x2 … - Sikademy
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Archangel Macsika

List the members of the following sets 1. {x| x is real numbers and x2 = 1} 2. {x| x is an integer and -4 < x ≤ 3} B. Use set builder notation to give description of each of these sets. 1. {a, e,i ,o, u} 2. {=2, -1, 0, 1, 2} C. Let A= (a, b, c), B = (x, y) and C = (0, 1) Find: 1. A U C 2. C x B 3. B – A 4. (A ∩ C) U B D. Find these terms of the sequence (An}, where An = 2(3)n + 5 1. A0 2. A5 3. A3 4. 8th term 5. 2nd term 6. Sum of the sequence E. Given the following set: 2. X = {-1, 0, 1, 2, 3, 4, 5} defined by the rule (x, y) ∈R if x ≤ y F. List the elements of R G. Find the domain of R H. Find the range of R I. Draw the digraph J. Properties of the Relation

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Solution:

(A):

1: \{ 1,-1\}

2: \{ -3,-2,-1,0,1,3\}

(B):

1: {x| x is a vowel }

2: {x| x is an integer and -2\le x\le2 }

(C):

1: A\cup C=\{ a,b,c,0,1\}

2: C\times B=\{ (0,x),(0,y),(1,x),(1,y)\}

3: B-A=\{ x,y\}

4: (A\cap C)\cup B=\{\phi\}\cup \{x,y\}=\{x,y\}

(D):

A_n=2(3)^n+5

(1): Put n = 0

A_0=2(3)^0+5=2(1)+5=7

(2): Put n = 5

A_5=2(3)^5+5=2(243)+5=491

(3): Put n = 3

A_3=2(3)^3+5=2(27)+5=59

(4): For 8th term, put n = 8

A_8=2(3)^8+5=2(6561)+5=13127

(5): For 2nd term, put n = 2

A_2=2(3)^2+5=2(9)+5=23

(6): S_n=\sum [2(3)^n+5]=2\sum 3^n+5\sum 1

=2(3^0+3^1+...+3^n)+5n \\=2[\dfrac{1(3^{n-1}-1)}{3-1}]+5n \ [\text{Using GP}] \\=3^{n-1}+5n-1

(E):

(F): R = {(-1,-1),(-1,0),(-1,1),(-1,2),(-1,3),(-1,4),(-1,5),(0,0),(0,1),(0,2),(0,3),(0,4),(0,5),(1,1),(1,2),(1,3),(1,4),(1,5),(2,2),(2,3),(2,4),(2,5),(3,3),(3,4),(3,5),(4,4),(4,5),(5,5)}

(G): Domain of R = {-1, 0, 1, 2, 3, 4, 5}

(H): Range of R = {-1, 0, 1, 2, 3, 4, 5}

(I): Digraph:



(J): This relation is reflexive and transitive but not symmetric as-

Reflexive: (x\le x), this is true

Transitive: \\(x\le y)\ \& (y\le z)\Rightarrow (x\le z), this is true

Symmetric: (x\le y)\Rightarrow (y\le x), this is not true.


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Question ID: mtid-5-stid-8-sqid-3282-qpid-1981