Solution to R= {(1,3) ,(1,4) , (3,2) , (3,3), (3,4)} on A={1,2,3,4} - Sikademy
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Archangel Macsika

R= {(1,3) ,(1,4) , (3,2) , (3,3), (3,4)} on A={1,2,3,4}

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Question is incomplete.

Let us take an example related to the given problem:

Let R= {(1,3) ,(1,4) , (3,2) , (3,3), (3,4)} be a relation on set A={1,2,3,4}. Then relation R is?

Answer:

R= {(1,3) ,(1,4) , (3,2) , (3,3), (3,4)}

It is seen that (a,a)\notin R , for every a∈\{1,2,3,4\}.

∴ R is not reflexive.

It is seen that (1,3)∈R , but (3,1) \notin R.

∴ R is not symmetric.

Also, it is observed that (a,b),(b,c)\in R⇒(a,c)\notin R\text{ for all }a,b,c∈\{1,2,3,4\}

∴ R is not transitive.

Hence,R neither is reflexive nor transitive nor symmetric.


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