Solution to Q(X,y):X+y >or=7 then what is truth value of∀x∃yQ(x,y) - Sikademy
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Q(X,y):X+y >or=7 then what is truth value of∀x∃yQ(x,y)

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 The answer depends on the set where the values of x, y are defined. Given ,

Q(x,y):x+y\ge7


\forall x \exist yQ(x, y)


For all value of x Let x=1 and y=1:



x+y=1+1=2<72\text{ is less than }7

Since x+y\le7 The truth value of Q is false for some values of x and y.


\text{At } x=8,y=2\\ X+y=8+2=10>7


then the truth value of Q(x, y) is true for some values of x and y

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