**a particular algorithm increases in time as the number of operations n increases. Suppose the time complexity of this algorithm is given by: f(n)=4n2+5n2*log(n) Show that f(n) is O(g(n)) for g(n) = n3**

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$f(n)=4n^2+5n^2log(n)\le4n^3+5n^3=9n^3=9g(n)$

so f(n) is O(g(n))

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Question ID: mtid-5-stid-8-sqid-782-qpid-667