Solution to prove that AUB = AU(B\A) - Sikademy
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Archangel Macsika

prove that AUB = AU(B\A)

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A ∪ (B − A) = A ∪ (B ∩ A^C) set difference


= A ∪ (A^C ∩ B) commutative


= (A ∪ A^C) ∩ (A ∪ B)   distributive


= U ∩ (A ∪ B) complement


= A ∪ B identity


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Question ID: mtid-5-stid-8-sqid-1366-qpid-1104