Prove that (p ∧ q) → (p ∨ q) is a tautology using the table of propositional equivalences.

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Using the following equivalence law (you can prove from a truth table):

$r\rightarrow s\equiv \lnot r\lor s$

Let $r = p\land q$ and $s = p\lor q$ , then

$(p\land q)\rightarrow (p\lor q)\equiv \lnot(p\land q)\lor(p\lor q).$

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Question ID: mtid-5-stid-8-sqid-3156-qpid-1855