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Let (6k + 1) be the first form and (6l + 1) be the second form
Product of both forms will be:
= (6k + 1)(6l + 1)
= 36kl + 6k + 6l + 1
= 6(6kl + k + l) + 1.
Thus, the product of two integers of the form 6n+1 is again of the form 6n + 1