Let us construct the trush table for the formula ∼(p∨q)→r:
p00001111q00110011r01010101p∨q00111111∼(p∨q)11000000∼(p∨q)→r01111111
We conclude that this formula neither tautology nor contradiction.
Let us construct the trush table for the formula ∼(p∨q)→r:
p00001111q00110011r01010101p∨q00111111∼(p∨q)11000000∼(p∨q)→r01111111
We conclude that this formula neither tautology nor contradiction.
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