~(~p^q) ^(pvq) =p

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$\neg(\neg p \wedge q)\wedge (p \vee q)=\\ (p \vee \neg q) \wedge (p \vee q)\{De Morgan's\}=\\ p \wedge (\neg q \vee q)\{Distributive\}=\\ p \wedge 1 \{ Identity\}=\\ p$ $\neg (\neg p \land q) \land (p \lor q) = (p \lor \neg q) \land (p \lor q) {De M or g a n^{'} s} = p \land (\neg q \lor q) {D i s t r ib u t i v e} = p \land 1 {I d e n t i t y} = p$

~(~p^q) ^(pvq) =p

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Question ID: mtid-5-stid-8-sqid-3203-qpid-1902