Show that ¬(p ⊕ q) and p ↔ q are logically equivalent

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Let us show that $¬(p ⊕ q)$ and $p ↔ q$ are logically equivalent using truth table:

$\begin{array}{||c|c||c|c|c|} \hline \hline p & q & p\oplus q & \neg(p\oplus q) & p ↔ q\\ \hline \hline F & F & F & T & T\\ \hline F & T & T & F & F\\ \hline T & F & T & F & F\\ \hline T & T & F & T & T\\ \hline \hline \end{array}$

Since the formulas on each pair have the same values, they are logically equivalent.

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Question ID: mtid-5-stid-8-sqid-3052-qpid-1751