Show that if x is an integer then x2+x-41= 0 produce prime numbers

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We have given ,

$x^2+x-41$

To show that if x is integer $x^2+x-41$ produces prime number.

This result cannot be proved because if suppose we take the integers less than 6 it gives negative values which is obviously not prime numbers.

If we take x = 6 it gives 1 which is again not a prime number.

If we take x= 7 it will give 15 which is again not a prime number.

Hence, it will not produce all prime number even if x is an integer.