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$a_n=a_{n-1}-4,a_0=1\\ a_1=a_0-4=1-4=-3\\ a_2=a_1-4=(1-4)-4\\ a_3=a_2-4=(1-4-4)-4\\ \vdots\\ a_n=1-4n$ $a_{n} = a_{n - 1} - 4, a_{0} = 1 a_{1} = a_{0} - 4 = 1 - 4 = - 3 a_{2} = a_{1} - 4 = (1 - 4) - 4 a_{3} = a_{2} - 4 = (1 - 4 - 4) - 4 ⋮ a_{n} = 1 - 4 n$

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Question ID: mtid-5-stid-8-sqid-3342-qpid-2041