Solution to State the Pigeonhole Principle. In a result sheet of a list of 60 students, each … - Sikademy
Author Image

Archangel Macsika

State the Pigeonhole Principle. In a result sheet of a list of 60 students, each marked “Pass” or “Fail “. There are 35 students pass. Show that there are at least two students pass in the list exactly nine students apart. (for example students at numbered 2 and 11 or at numbered 50 and 59 satisfy the condition).

The Answer to the Question
is below this banner.

Can't find a solution anywhere?

NEED A FAST ANSWER TO ANY QUESTION OR ASSIGNMENT?

Get the Answers Now!

You will get a detailed answer to your question or assignment in the shortest time possible.

Here's the Solution to this Question

pigeonhole principle states that if n items are put into m containers, with n>m, then at least one container must contain more than one item.


There are 25 students "fail". There are 30 pairs of students in the list exactly nine

students apart. So, by pigeonhole principle, there are at least 2 pairs of students "pass" in this list.

Related Answers

Was this answer helpful?

Join our Community to stay in the know

Get updates for similar and other helpful Answers

Question ID: mtid-5-stid-8-sqid-757-qpid-642