Solution to State the Pigeonhole Principle. Prove that if six integers are selected from the set [3,4,5,6,7,8,9,10,11,12] … - Sikademy
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State the Pigeonhole Principle. Prove that if six integers are selected from the set [3,4,5,6,7,8,9,10,11,12] there must be two integer whose sum is fifteen.

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For natural numbers {\displaystyle k}  and {\displaystyle m}, if {\displaystyle n=km+1} objects are distributed among {\displaystyle m} sets, then the Pigeonhole Principle asserts that at least one of the sets will contain at least {\displaystyle k+1}  objects.


Let us consider the partition of the set \{3,4,5,6,7,8,9,10,11,12\} ito 5 subset: \{3,12\}\{4,11\}\{5,10\}, \{6,9\} and \{7,8\}. The sum of elements in each subset is equal to 15. Taking into account that there are 5 subsets and we choose 6 elements by Pigeonhole Principle we get that at least one pair will be selected. Consequently, there must be two integer whose sum is fifteen.


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Question ID: mtid-5-stid-8-sqid-786-qpid-671