Suppose that a department contains 8 men and 20 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?
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Since we have to form a committee of 6 members with strictly more women means that there can be either 4 or 5 or all 6 women in the committee which can be formed in the following number of ways,
8C2*20C4 + 8C1*20C5 + 8C0*20C6
Formula for combination =
Substituting the values of n & r in the above formula we get,
8C2*20C4 + 8C1*20C5 + 8C0*20C6 =298452
Hence we can form a committee of 6 members in 298452 ways if it must have strictly more women than men