The Answer to the Question
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Here's the Solution to this Question
(a) Using two bits for each letter, we can represent different letters.
But here are 5 letters (B, D, E, G, U). So we will need three bits for each letter. Because maximum letters can be represented using 3 bits.
Now total frequency = 55+15+80+5+45=200
Hence total bits required bits.
Total bits by Huffman