Solution to There are 3 black balls, 4 blue balls and 5 red balls in a box. … - Sikademy
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Archangel Macsika

There are 3 black balls, 4 blue balls and 5 red balls in a box. In how many ways can we choose 3 balls at the same time with different colors?

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Taking into account that there are 3 black balls, 4 blue balls and 5 red balls in a box, we conclude by Combinatorial Product Rule that the number of ways we can choose 3 balls at the same time with different colors is equal to 3\cdot 4\cdot 5=60.


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Question ID: mtid-5-stid-8-sqid-1417-qpid-1155