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Total no. of friends = 6 (Ajay, Bob, Chintu, Devi, Emily and Fatima)
Number of teams = 3
Each team must have at least one player but Chintu does not want to be alone in a team. So, total number of ways to form three teams with at least one member in a team will be:
Number of required ways to form teams = (Chintu and one player + Two other players + Two remaining players) + (Chintu and two players + Two other players + one remaining player)
= [1 * (5C1 + 4C2 + 2C2) + [1 * (5C2 + 4C2 + 2C2)
= (5 + 6 + 1) + (10 + 6 + 1)
This means there are total 29 ways to form three teams with at least one member in a team.