Solution to Total number of stalls for animals in exhibition = 10 Number of each of three … - Sikademy
Author Image

Archangel Macsika

Total number of stalls for animals in exhibition = 10 Number of each of three type animal = at least 10 Types of animals = 3 (animals; lion, pussycat) Then, possible number of ways of arranging the exhibition are: 3^{10}=3\times3\times3\times3\times3\times3\times3\times3\times3\times3=590493 10 =3×3×3×3×3×3×3×3×3×3=59049 There are total 59049 ways to fill the 10 stalls in exhibition.

The Answer to the Question
is below this banner.

Can't find a solution anywhere?

NEED A FAST ANSWER TO ANY QUESTION OR ASSIGNMENT?

Get the Answers Now!

You will get a detailed answer to your question or assignment in the shortest time possible.

Here's the Solution to this Question

Solution:

The numbers of three digits can be formed with the digits 1, 2, 3, 4 and 5 if the digits in the same number are not repeated =5\times 4\times3=60


Three digit numbers: 5 \times 4 \times 3 = 60

Four digit numbers: 5 \times\times 3 \times 2 = 120

Five digit numbers: 0 (Because they’d be bigger than 10,000).

Total: 180 numbers

Related Answers

Was this answer helpful?

Join our Community to stay in the know

Get updates for similar and other helpful Answers

Question ID: mtid-5-stid-8-sqid-493-qpid-380