Total number of stalls for animals in exhibition = 10 Number of each of three type animal = at least 10 Types of animals = 3 (animals; lion, pussycat) Then, possible number of ways of arranging the exhibition are: 3^{10}=3\times3\times3\times3\times3\times3\times3\times3\times3\times3=590493 10 =3×3×3×3×3×3×3×3×3×3=59049 There are total 59049 ways to fill the 10 stalls in exhibition.
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Solution:
The numbers of three digits can be formed with the digits 1, 2, 3, 4 and 5 if the digits in the same number are not repeated
Three digit numbers: 5 4 3 = 60
Four digit numbers: 5 4 3 2 = 120
Five digit numbers: 0 (Because they’d be bigger than 10,000).
Total: 180 numbers