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Use strong induction to prove that every integer n > 5 can be written as n = 4x + 3y for non-negative x, y ∈ Z.

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I prove using strong induction that for any n>5 P(n): n=4x+3y holds.

Base cases:

n=6: P(6): 6=4*0+3*2, thus x=0 and y=2

n=7: P(7): 7=4*1+3*1, thus x=y=1

I took two base cases because we’ll need to go two steps backwards in the induction step (k-2).

Induction step:

We assume that P(6)  P(7) ……. P(k) is true for a positive integer k greater than or equal to 8.

We must prove that P(k+1) also holds.

Since k is greater than or equal to 8 => 5<k-2 < k, thus P(k-2) holds, so we can apply the induction hypothesis.

So, k-2=4x+3y => k+1=(k-2)+3=4x+3y+3=4x+3(y+1) which proves that k+1 has the same form.

We have proved that P(6)  P(7) ……. P(k-2) => P(k+1)

According to strong induction principle, the proof is now complete and P(n) holds for any n>5. 


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Question ID: mtid-5-stid-8-sqid-4053-qpid-2752