Use the truth table to transform each of the following wffs into the full conjunctive normal form (P→Q)→P. P→(Q→P) (P∨Q)∧R. P→Q∧R. Q∧¬P→P

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a. (P→Q)→P = P

b. P→(Q→P) = 1

c. (P∨Q)∧R

d. P→Q∧R = (Q ∧ R) ∨ ¬P

e. Q∧¬P→P = P ∨ ¬Q

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Question ID: mtid-5-stid-8-sqid-3112-qpid-1811