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## Here's the Solution to this Question

``````
#include <iostream>
using namespace std;

int main()
{
//a. Prompt the user to input two integers: firstNum and secondNum
//(firstNum must be less than secondNum).
cout << "a. Prompt the user to input two integers. First must be less than second\n";
double firstNum = 2;
double secondNum = 1;

while (firstNum > secondNum)
{
cout << "enter first number: \n";
cin >> firstNum;
cout << "enter second number (must be more than first number): \n";
cin >> secondNum;

if (firstNum > secondNum)
cout << "first number must be less than second number. Try again. \n";
}
cout << "\n";

//b. Output all odd numbers between firstNum and secondNum.
cout << "b. Output all odd numbers between firstNum and secondNum.\n";
int number = firstNum;

while (number <= secondNum)
{
if (number % 2)
cout << number++ << "\n";
else
{
number++;
continue;
}
}
cout<<"\n";

//c. Output the sum of all even numbers between firstNum and secondNum.
cout << "c. Output the sum of all even numbers between firstNum and secondNum.\n";
number = firstNum;
int sum = 0;

while (number <= secondNum)
{
if (!(number % 2))
sum += number++;
else
{
number++;
continue;
}
}
cout << "sum = " << sum << "\n\n";

//d. Output the numbers and their squares between 1 and 10.
cout << "d.Output the numbers and their squares between 1 and 10.\n";
number = 1;
while (number <= 10)
{
cout << number << " -> " << number << "^2" << " = " << number * number << '\n';
number++;
}
cout << "\n";

//e. Output the sum of the square of the odd numbers between firstNum and secondNum.
cout << "Output the sum of the square of the odd numbers between firstNum and secondNum\n";
number = firstNum;
sum = 0;
while (number <= secondNum)
{
if (number % 2)
{
sum += (number * number);
number++;
}
else
{
number++;
continue;
}
}
cout << "sum: " << sum << "\n\n";

//f. Output all uppercase letters.
cout << "Output all uppercase letters.\n";
int c = 65;

while (c < 91)
cout << char(c++) << ", ";
cout << "\n";
}``````