Solution to An electrical firm manufactures light bulbs that have a length of life that is normally … - Sikademy
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Archangel Macsika

An electrical firm manufactures light bulbs that have a length of life that is normally distributed with mean equal to 778 hours and a standard deviation of 40 hours. Find the probability that a bulb burns between 710 and 841 hours.

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Let X= a length of life: X\sim N(\mu, \sigma^2).

Given \mu=778\ h, \sigma=40\ h.


P(710<X<841)=P(X<841)-P(X\le 710)

=P(Z<\dfrac{841-778}{40})-P(Z\le \dfrac{710-778}{40})

= P(Z<1.575)-P(X\le -1.7)

\approx0.94237-0.04457= 0.8978


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